66 lines
2.0 KiB
Python
66 lines
2.0 KiB
Python
#!/usr/bin/env python
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import sys
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from subprocess import call
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import os
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from pysftp import Connection
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from tkinter import Tk, Button
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from string import ascii_letters, digits
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from random import choices
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import config
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character_pool = ascii_letters + digits
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def find_filename(prefix, length, ext, conn):
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def generate_filename(prefix, length, ext):
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return prefix + ''.join(choices(character_pool, k=length)) + '.' + ext
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filename = generate_filename(prefix, length, ext)
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i = 0
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while conn.exists(filename):
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filename = generate_filename(prefix, length, ext)
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i += 1
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if i > 1000:
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# using recursion here feels... questionable at best, but it's faster than using % every loop
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find_filename(prefix, length + 1, ext, conn)
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def upload_local_file(path: str, conn: Connection):
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raise NotImplementedError('soon(tm)')
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def upload_screenshot(filename: str, conn: Connection):
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call(["escrotum", "{}".format(filename), "-s"])
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conn.put(filename)
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def prepare_upload(mode='screenshot', ext=None) -> str:
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if mode == 'screenshot' and ext == None:
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ext = 'png'
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with Connection(config.sftp_address, username=config.username, password=config.password) as conn:
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with conn.cd(config.remote_directory):
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filename = find_filename(config.prefix, config.length, ext, conn) + '.{}'.format(ext)
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filepath = os.path.join(config.local_directory, filename)
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return filepath
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link = config.link_template.format(filename)
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# copy link to clipboard
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# https://stackoverflow.com/questions/579687/how-do-i-copy-a-string-to-the-clipboard-on-windows-using-python#4203897
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print(link)
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r = Tk()
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r.clipboard_clear()
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r.clipboard_append(link)
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r.after(2000, sys.exit)
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# also show a little button that does nothing.
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# Well, it informs you that your link is ready, so that's something, I guess
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rButton = Button(r, text=f"{link}", font=("Verdana", 12), bg="black", command=sys.exit)
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rButton.pack()
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r.geometry('400x50+700+500')
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r.mainloop()
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